What is the extreme f(x)=(x+1)^5-5x-3 ?

The extreme f(x)=(x+1)^5-5x-3 is Maximum(-2,6),Minimum(0,-2)

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extreme f(x)=(x+1)^5-5x-3

extreme points

f (x) = (x + 1)^{5} - 5 x - 3

Maximum (- 2, 6), Minimum (0, - 2)

Solution steps

f^{'} (x) = 5 x^{4} + 20 x^{3} + 30 x^{2} + 20 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

(x + 1)^{5} - 5 x - 3 : 6

Maximum (- 2, 6)

Plug

x = 0

into

(x + 1)^{5} - 5 x - 3 : - 2

Minimum (0, - 2)

Maximum (- 2, 6), Minimum (0, - 2)

a^{3} y = x^{2} (2 a^{2} x^{2})

f (x, y) = x^{3} - 15 x y + y^{3}

f (x) = x^{3} - 5 x^{2} - 8 x + 3

f (x) = 2 x^{2} + 3 y^{2} - 4 x - 12 y + 13

f (x) = 5 - 6 x^{2} - 2 x^{3}

What is the extreme f(x)=(x+1)^5-5x-3 ?
The extreme f(x)=(x+1)^5-5x-3 is Maximum(-2,6),Minimum(0,-2)