What is the extreme f(x)=x^2-6,(-2,4) ?

The extreme f(x)=x^2-6,(-2,4) is Minimum(0,-6)

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extreme f(x)=x^2-6,(-2,4)

extreme points

f (x) = x^{2} - 6, (- 2, 4)

Minimum (0, - 6)

Solution steps

Find the critical points:

x = 0

Domain of

x^{2} - 6, (- 2, 4) : - 2 < x < 4

Find intervals:

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 4

Plug the extreme point

x = 0

into

x^{2} - 6 \Rightarrow y = - 6

Minimum (0, - 6)

2 x^{3} + 3 x^{2} + 12 x - 4

B (1 + p)

f (x) = - x^{3} - 9 x^{2} - 15 x + 1

f (x, y) = 4 y^{2} + 5 x^{2} - 9 y + 8 x - 19

f (x) = 8 x^{2} + 8 x y + 10 y^{2} - 24 x - 28 y + 27

What is the extreme f(x)=x^2-6,(-2,4) ?
The extreme f(x)=x^2-6,(-2,4) is Minimum(0,-6)