What is the extreme 2x^3+6xy^2-3y^3-150x ?

The extreme 2x^3+6xy^2-3y^3-150x is Saddle(3,4),Saddle(-3,-4)

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extreme 2x^3+6xy^2-3y^3-150x

extreme points

2 x^{3} + 6 x y^{2} - 3 y^{3} - 150 x

Saddle (3, 4), Saddle (- 3, - 4)

Solution steps

Find the critical points:

(3, 4), (- 3, - 4)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 18 y + 12 x

D (x, y) = 12 x (- 18 y + 12 x) - 144 y^{2}

Check the sign of at each critical point

Check critical point

(3, 4) :

Saddle

Check critical point

(- 3, - 4) :

Saddle

Saddle (3, 4), Saddle (- 3, - 4)

f (x) = x^{3} - 2 x^{2} - 15 x + 10, - 2 \leq x \leq 0

f (x, y) = 2 x^{4} - 5 x^{2} y^{3} - 3 x y^{4}

f (x) = 2 x^{2} - 4 x + 2

f (x) = x^{3} - 9 x^{2} + 4

f (x) = \frac{1}{16 - x ^{2} + 4 y ^{2}}

What is the extreme 2x^3+6xy^2-3y^3-150x ?
The extreme 2x^3+6xy^2-3y^3-150x is Saddle(3,4),Saddle(-3,-4)