What is the extreme f(x)=x_{1}x ?

The extreme f(x)=x_{1}x is Saddle(0,0)

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extreme f(x)=x_{1}x

extreme points

f (x) = x_{1} x

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, x_{1}) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

0.5 x^{2} - 130 x + 17555

f (x, y) = x - y - x^{2} y + x y^{2}

f (x) = x^{4} - 6 x^{2} + 9, 0 \leq x \leq 2

\frac{4 - x ^{2}}{x}

f (x) = e^{- k x}