What is the extreme f(x,y)=2x^2-xy-3y^2-3x+7y ?

The extreme f(x,y)=2x^2-xy-3y^2-3x+7y is Saddle(1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=2x^2-xy-3y^2-3x+7y

extreme points

f (x, y) = 2 x^{2} - x y - 3 y^{2} - 3 x + 7 y

Saddle (1, 1)

Solution steps

Find the critical points:

(1, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = - 25

Check the sign of at each critical point

Check critical point

(1, 1) :

Saddle

Saddle (1, 1)

f (x, y) = x^{3} + 6 x y + y^{3}

f (x, y) = x y - 5 x + 15

f (x, y) = ln (4 x^{2} + 9 y^{2} + 36)

f (x) = \frac{x}{x ^{2} + 5 x + 4}

2 ln (1 + x^{2})

What is the extreme f(x,y)=2x^2-xy-3y^2-3x+7y ?
The extreme f(x,y)=2x^2-xy-3y^2-3x+7y is Saddle(1,1)