What is the extreme f(x,y)= 10/3 xy+xy^2 ?

The extreme f(x,y)= 10/3 xy+xy^2 is Saddle(0,0),Saddle(0,-10/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)= 10/3 xy+xy^2

extreme points

f (x, y) = \frac{10}{3} x y + x y^{2}

Saddle (0, 0), Saddle (0, - \frac{10}{3})

Solution steps

Find the critical points:

(0, 0), (0, - \frac{10}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2 x

D (x, y) = - 4 y^{2} - \frac{40}{3} y - \frac{100}{9}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Check critical point

(0, - \frac{10}{3}) :

Saddle

Saddle (0, 0), Saddle (0, - \frac{10}{3})

f (x) = - 2 x^{2} + 8 x - 1

f (x) = 4 cos (2 x) - 4

h (t, v) = - 16 t^{2} + v t + c

f (x) = 6 x^{5} - 160 x^{3} + 26

f (x) = x^{3} - 12 x - 8

What is the extreme f(x,y)= 10/3 xy+xy^2 ?
The extreme f(x,y)= 10/3 xy+xy^2 is Saddle(0,0),Saddle(0,-10/3)