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Popular >

extreme f(x)=x^2+2x-15

Solution

extreme points

f (x) = x^{2} + 2 x - 15

Solution

Minimum (- 1, - 16)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x - 15 : - 16

Minimum (- 1, - 16)

Popular Examples

extreme y=2x^3-3x^2+6 extreme points

y = 2 x^{3} - 3 x^{2} + 6

extreme f(x)=x^2-2x^4 extreme points

f (x) = x^{2} - 2 x^{4}

extreme f(x)=(x-8)e^x extreme points

f (x) = (x - 8) e^{x}

extreme y=6t^2-42t-60 extreme points

y = 6 t^{2} - 42 t - 60

extreme y=y=(x^3)/3+(x^2)/2-2x+9 extreme points

y = y = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x-15 ?
The extreme f(x)=x^2+2x-15 is Minimum(-1,-16)