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Popular >

extreme f(x)=x^2-8

Solution

extreme points

f (x) = x^{2} - 8

Solution

Minimum (0, - 8)

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} - 8 : - 8

Minimum (0, - 8)

Popular Examples

extreme f(x)=(-2)/(x^2-9)extreme points

f (x) = \frac{- 2}{x ^{2} - 9}

extreme f(x)=-x^4+3x^3+18 extreme points

f (x) = - x^{4} + 3 x^{3} + 18

extreme f(x,y)=ln(y+x)extreme points

f (x, y) = ln (y + x)

extreme f(x,y)=xe^y+y+1 extreme points

f (x, y) = x e^{y} + y + 1

extreme f(x)=sin(x)-cos(x),0<= x<= pi extreme points

f (x) = sin (x) - cos (x), 0 \leq x \leq π

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8 ?
The extreme f(x)=x^2-8 is Minimum(0,-8)