What is the extreme f(x)=x^3-3x,-1<= x<= 2 ?

The extreme f(x)=x^3-3x,-1<= x<= 2 is Maximum(-1,2),Minimum(1,-2),Maximum(2,2)

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extreme f(x)=x^3-3x,-1<= x<= 2

extreme points

f (x) = x^{3} - 3 x, - 1 \leq x \leq 2

Maximum (- 1, 2), Minimum (1, - 2), Maximum (2, 2)

Solution steps

Find the critical points:

x = - 1, x = 1, x = 2

Domain of

x^{3} - 3 x, - 1 \leq x \leq 2 : - 1 \leq x \leq 2

Find intervals:

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < 2

Plug the extreme point

x = - 1

into

x^{3} - 3 x \Rightarrow y = 2

Maximum (- 1, 2)

Plug the extreme point

x = 1

into

x^{3} - 3 x \Rightarrow y = - 2

Minimum (1, - 2)

Plug the extreme point

x = 2

into

x^{3} - 3 x \Rightarrow y = 2

Maximum (2, 2)

Maximum (- 1, 2), Minimum (1, - 2), Maximum (2, 2)

\frac{d}{d r} (4 k^{\frac{3}{2}} (\frac{r}{w}))

f (x) = x + 10 1 - x, - 2 \leq x \leq 5

f (x) = 2 x^{3} + x^{2} - 11 x

y = x^{5}

f (x) = 5 y - 5 x + x y - 10

What is the extreme f(x)=x^3-3x,-1<= x<= 2 ?
The extreme f(x)=x^3-3x,-1<= x<= 2 is Maximum(-1,2),Minimum(1,-2),Maximum(2,2)