What is the critical f(x)=(ln(x))/(x^2) ?

The critical f(x)=(ln(x))/(x^2) is x=sqrt(e)

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critical f(x)=(ln(x))/(x^2)

critical points

f (x) = \frac{ln ( x )}{x ^{2}}

x = e

Solution steps

\frac{ln ( x )}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = e, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{ln ( x )}{x ^{2}} : x > 0

\frac{ln ( x )}{x ^{2}}

is not defined at

x = 0

, therefore:

x = e

f (x) = x^{2} e^{- x}

f (x, y) = x^{3} y + 12 x^{2} - 8 y

f (x) = x^{2} ln (x)

\frac{3 x ^{2}}{∣ x - 1 ∣}

\frac{d}{d x} (\frac{x y}{x ^{2} + y ^{2}})

What is the critical f(x)=(ln(x))/(x^2) ?
The critical f(x)=(ln(x))/(x^2) is x=sqrt(e)