What is the critical f(x)=x-ln(x) ?

The critical f(x)=x-ln(x) is x=1

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critical f(x)=x-ln(x)

critical points

f (x) = x - ln (x)

x = 1

Solution steps

x - ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

x - ln (x) : x > 0

x - ln (x)

is not defined at

x = 0

, therefore:

x = 1

f (x) = \frac{y - 5}{y ^{2} - 3 y + 15}

f (x) = 4 + x^{3} + y^{3} - 3 x y

f (x) = x y^{2} + 2 x y + 3 x^{3} - 3 x

6 x^{2} - x^{3}

\frac{x}{x ^{2} + 9}