What is the critical y= x/(x^2-9) ?

The critical y= x/(x^2-9) is None

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critical y= x/(x^2-9)

critical points

y = \frac{x}{x ^{2} - 9}

None

Solution steps

\frac{x}{x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} - 9} : x < - 3 or - 3 < x < 3 or x > 3

\frac{x}{x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

f (x, y) = 9 - 2 x + 4 y - x^{2} - 4 y^{2}

x^{2} + y^{2} + x y

y = x^{2}

f (x) = \frac{x ^{2} + 1}{x ^{2} - 4}

f (x) = x - \frac{1}{2} y^{2} - \frac{1}{3} x^{3} + y + 6