What is the critical f(x)=(x^2)/(sqrt(x+1)) ?

The critical f(x)=(x^2)/(sqrt(x+1)) is x=0

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critical f(x)=(x^2)/(sqrt(x+1))

critical points

f (x) = \frac{x ^{2}}{x + 1}

x = 0

Solution steps

\frac{x ^{2}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x + 1} : x > - 1

\frac{x ^{2}}{x + 1}

is not defined at

x = - 1

, therefore:

x = 0

f (x) = \frac{e ^{4 x}}{x + 1}

x - 3 x^{\frac{1}{3}}

f (x) = (x - 4)^{2} + 10

f (x, y) = (x^{2} + y^{2}) e^{y^{2} - x^{2}}

f (x, y) = 100 + 4 x - 9 y + 2 x y - x^{2} + y^{3}

What is the critical f(x)=(x^2)/(sqrt(x+1)) ?
The critical f(x)=(x^2)/(sqrt(x+1)) is x=0