What is the critical (x^2+2)/(2x-1) ?

The critical (x^2+2)/(2x-1) is x=-1,x=2

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critical (x^2+2)/(2x-1)

critical points

\frac{x ^{2} + 2}{2 x - 1}

x = - 1, x = 2

Solution steps

\frac{x ^{2} + 2}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 2}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

\frac{x ^{2} + 2}{2 x - 1}

is not defined at

x = \frac{1}{2}

, therefore:

x = - 1, x = 2

x y

f (x) = \frac{x ^{4} + 1}{x ^{2}}

f (x) = cos^{2} (x) + sin (x)

y = \frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x + 8

f (x) = 20 x^{3} - 3 x^{5}