What is the critical f(x)=3x^2y+y^3-3x^2-3y^2+2 ?

The critical f(x)=3x^2y+y^3-3x^2-3y^2+2 is (0,2),(0,0),(1,1),(-1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=3x^2y+y^3-3x^2-3y^2+2

critical points

f (x) = 3 x^{2} y + y^{3} - 3 x^{2} - 3 y^{2} + 2

(0, 2), (0, 0), (1, 1), (- 1, 1)

Solution steps

3 x^{2} y + y^{3} - 3 x^{2} - 3 y^{2} + 2

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 2), (0, 0), (1, 1), (- 1, 1)

f (x) = (ln (x))^{2}

f (x) = x^{4} - 4 x^{2} + 4

f (x) = \frac{x ^{2}}{( x - 1 )}

f (x, y) = x^{3} - y^{3} - 2 x y + 6

\frac{d}{d x} (\frac{2 x y}{x ^{2} + 2 y ^{2}})

What is the critical f(x)=3x^2y+y^3-3x^2-3y^2+2 ?
The critical f(x)=3x^2y+y^3-3x^2-3y^2+2 is (0,2),(0,0),(1,1),(-1,1)