What is the critical x/(sqrt(x^2-9)) ?

The critical x/(sqrt(x^2-9)) is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical x/(sqrt(x^2-9))

critical points

\frac{x}{x ^{2} - 9}

None

Solution steps

\frac{x}{x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} - 9} : x < - 3 or x > 3

\frac{x}{x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

y = x^{3} + 9 x^{2} + b

f (x, y) = x^{3} + y^{3} - x y

f (x, y) = - x^{4} - 32 x + y^{3} - 12 y + 7

f (x) = \frac{x - 4}{- 4 x ^{2} + 4}

f (x, y) = x^{3} y + 6 x^{2} - y