What is the critical ln(x+2)(x-1)^2 ?

The critical ln(x+2)(x-1)^2 is x=(3-4\W_{0}((3e^{1/2})/2))/(2\W_{0)((3e^{1/2})/2)},x=1

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critical ln(x+2)(x-1)^2

critical points

ln (x + 2) (x - 1)^{2}

x = \frac{3 - 4 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}{2 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}, x = 1

Solution steps

ln (x + 2) (x - 1)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3 - 4 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}{2 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}, x = 1, x = - 2

Identify critical points not in

f (x)

domain

Domain of

ln (x + 2) (x - 1)^{2} : x > - 2

ln (x + 2) (x - 1)^{2}

is not defined at

x = - 2

, therefore:

x = \frac{3 - 4 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}{2 W _{0} ( \frac{3 e ^{\frac{1}{2}}}{2} )}, x = 1

f (x, y) = x^{2} + 2 y^{2} - x^{2} y

\frac{x ^{2} - 3}{x + 2}

f (x) = (x - 8) e^{x}

f (x) = (x^{2} + y^{2}) e^{x^{2} - y^{2}}

f (x, y) = x y^{3} + x^{2}

What is the critical ln(x+2)(x-1)^2 ?
The critical ln(x+2)(x-1)^2 is x=(3-4\W_{0}((3e^{1/2})/2))/(2\W_{0)((3e^{1/2})/2)},x=1