What is the critical f(x)=6x+4x^{-1} ?

The critical f(x)=6x+4x^{-1} is x=-sqrt(2/3),x=sqrt(2/3)

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critical f(x)=6x+4x^{-1}

critical points

f (x) = 6 x + 4 x^{- 1}

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

6 x + 4 x^{- 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

6 x + 4 x^{- 1} : x < 0 or x > 0

6 x + 4 x^{- 1}

is not defined at

x = 0

, therefore:

x = - \frac{2}{3}, x = \frac{2}{3}

f (x) = 3 x^{3} + x y^{2} - 2 x y + 1

f (x) = 3 x^{2} - 1

f (x) = x^{3} - 3 x^{2} + 3 x + 5

f (x) = - \frac{8 x}{x ^{2} - 4}

f (x) = x x + 2

What is the critical f(x)=6x+4x^{-1} ?
The critical f(x)=6x+4x^{-1} is x=-sqrt(2/3),x=sqrt(2/3)