What is the domain of f(x)=sqrt(3-x) ?

The domain of f(x)=sqrt(3-x) is x<= 3

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domain of f(x)=sqrt(3-x)

domain

f (x) = 3 - x

x \leq 3

Interval Notation

(- \infty, 3]

Solution steps

Find non-negative values for radicals:

x \leq 3

The function domain

x \leq 3

f (x) = 3 - t^{2}

f (x) = x^{2} - 4 x + 1

f (x) = 2 x e^{- 5 x}

f (x) = \frac{- 2}{x + 3}

\frac{1}{x}