What is the critical f(x,y)=6y^2+4x^2-12xy-4y ?

The critical f(x,y)=6y^2+4x^2-12xy-4y is (-1,-2/3)

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critical f(x,y)=6y^2+4x^2-12xy-4y

critical points

f (x, y) = 6 y^{2} + 4 x^{2} - 12 x y - 4 y

(- 1, - \frac{2}{3})

Solution steps

6 y^{2} + 4 x^{2} - 12 x y - 4 y

Find where

\nabla f (x, y)

is equal to zero or undefined

(- 1, - \frac{2}{3})

2 x^{3} - 15 x^{2} - 36 x

f (x) = x^{3} - 12 x + 4

8 x^{2} - x^{4}

f (x) = \frac{ln ( x )}{x}

f (x) = x^{3} + y^{3}

What is the critical f(x,y)=6y^2+4x^2-12xy-4y ?
The critical f(x,y)=6y^2+4x^2-12xy-4y is (-1,-2/3)