What is the critical f(x)=(ln(x))/(sqrt(x)) ?

The critical f(x)=(ln(x))/(sqrt(x)) is x=e^2

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critical f(x)=(ln(x))/(sqrt(x))

critical points

f (x) = \frac{ln ( x )}{x}

x = e^{2}

Solution steps

\frac{ln ( x )}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = e^{2}, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{ln ( x )}{x} : x > 0

\frac{ln ( x )}{x}

is not defined at

x = 0

, therefore:

x = e^{2}

f (x) = x^{3} + y^{3}

f (x) = 3 x^{4} - 4 x^{3} + 2

f (x) = \frac{1}{3} x^{3} - 9 x + \frac{1}{3} y^{3} - 4 y

f (x) = 6 cos (x) + 3 sin^{2} (x)

f (x) = x y + \frac{8}{x} + \frac{8}{y}

What is the critical f(x)=(ln(x))/(sqrt(x)) ?
The critical f(x)=(ln(x))/(sqrt(x)) is x=e^2