What is the critical f(x)=(e^{4x})/(x+3) ?

The critical f(x)=(e^{4x})/(x+3) is x=-11/4

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critical f(x)=(e^{4x})/(x+3)

critical points

f (x) = \frac{e ^{4 x}}{x + 3}

x = - \frac{11}{4}

Solution steps

\frac{e ^{4 x}}{x + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{11}{4}, x = - 3

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{4 x}}{x + 3} : x < - 3 or x > - 3

\frac{e ^{4 x}}{x + 3}

is not defined at

x = - 3

, therefore:

x = - \frac{11}{4}

f (x) = - x^{2} - 3 x + 3

f (x, y) = x^{3} - x + y^{3} - y

f (x) = x^{5} - x^{3}

x + ln (x^{2} - 8)

y = x^{3} - 3 x

What is the critical f(x)=(e^{4x})/(x+3) ?
The critical f(x)=(e^{4x})/(x+3) is x=-11/4