What is the critical f(x)=(x^2)/((x-2)^2) ?

The critical f(x)=(x^2)/((x-2)^2) is x=0

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critical f(x)=(x^2)/((x-2)^2)

critical points

f (x) = \frac{x ^{2}}{( x - 2 ) ^{2}}

x = 0

Solution steps

\frac{x ^{2}}{( x - 2 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{( x - 2 ) ^{2}} : x < 2 or x > 2

\frac{x ^{2}}{( x - 2 ) ^{2}}

is not defined at

x = 2

, therefore:

x = 0

y = \frac{x ^{2} - 1}{2 x - 1}

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} - 4}

f (x) = \frac{x}{x + 3}

f (x) = \frac{x ^{7} - 4 x ^{6} - 16 x ^{5} + 64 x ^{4}}{x}

f (x, y) = x^{2} + y^{4} + 2 x y

What is the critical f(x)=(x^2)/((x-2)^2) ?
The critical f(x)=(x^2)/((x-2)^2) is x=0