What is the critical f(x)= x/(2x^2-1) ?

The critical f(x)= x/(2x^2-1) is None

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critical f(x)= x/(2x^2-1)

critical points

f (x) = \frac{x}{2 x ^{2} - 1}

None

Solution steps

\frac{x}{2 x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{2 x ^{2} - 1} : x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

\frac{x}{2 x ^{2} - 1}

is not defined at

x = - \frac{1}{2}, x = \frac{1}{2}

, therefore:

None

P (x, y) = 2 x^{3} + 3 x^{2} y - 2 x y^{2} - 3 y^{3}

x^{3} - 6 x^{2} + 2

f (x) = e^{- 3.5 x^{2}}

f (x) = 3 x ln (x)

4 y^{3} - 2 x^{3} - y^{2} + 2 x - y