What is the critical f(x)=(x+4)/(\sqrt[3]{x+1)} ?

The critical f(x)=(x+4)/(\sqrt[3]{x+1)} is x= 1/2

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critical f(x)=(x+4)/(\sqrt[3]{x+1)}

critical points

x = \frac{1}{2}

Solution steps

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{2}, x = - 1

Identify critical points not in

f (x)

domain

Domain of

is not defined at

x = - 1

, therefore:

x = \frac{1}{2}

f (x, y) = 2 x^{2} + a x y + 3 y^{2} - 2 x + 1

+ 3 (x - 3)^{2} - 1

f (x) = x^{3} + 6 x^{2} + 9 x + 3

f (x) = x^{3} + 4 x^{2} + 4 x - 6

f (x) = 2 x^{2} + y^{4} - 2 x^{2} y^{2} + 3

What is the critical f(x)=(x+4)/(\sqrt[3]{x+1)} ?
The critical f(x)=(x+4)/(\sqrt[3]{x+1)} is x= 1/2