What is the critical f(x)=2x^2+y^4-2x^2y^2+3 ?

The critical f(x)=2x^2+y^4-2x^2y^2+3 is (0,0),(1,-1),(-1,-1),(1,1),(-1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=2x^2+y^4-2x^2y^2+3

critical points

f (x) = 2 x^{2} + y^{4} - 2 x^{2} y^{2} + 3

(0, 0), (1, - 1), (- 1, - 1), (1, 1), (- 1, 1)

Solution steps

2 x^{2} + y^{4} - 2 x^{2} y^{2} + 3

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (1, - 1), (- 1, - 1), (1, 1), (- 1, 1)

f (x) = 5 x^{2} - 3 x - 4

f (x) = x^{3} + \frac{3}{x}

f (x) = x^{3} + x - 1

f (x) = \frac{2 x + 3}{x + 2}

x x - x^{2}

What is the critical f(x)=2x^2+y^4-2x^2y^2+3 ?
The critical f(x)=2x^2+y^4-2x^2y^2+3 is (0,0),(1,-1),(-1,-1),(1,1),(-1,1)