频率 9cos(1/3 x+3/4)

解答

频率

9 cos (\frac{1}{3} x + \frac{3}{4})

\frac{1}{6 π}

求解步骤

f (x) = 9 cos (\frac{1}{3} x + \frac{3}{4})

g (B x - C) = cos (\frac{1}{3} x + \frac{3}{4}), B = \frac{1}{3}

\frac{B}{2 π} = \frac{\frac{1}{3}}{2 π}

\frac{1}{6 π}

f (x) = x^{3} - 3 x^{2} + 4

\frac{x}{x ^{2} + 243}

y = 7 x

f (x) = (x + 2)^{\frac{2}{3}}

f (x) = x^{2} + 6 x