What is the critical f(x)=((4x-12))/((x-2)^2) ?

The critical f(x)=((4x-12))/((x-2)^2) is x=4

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critical f(x)=((4x-12))/((x-2)^2)

critical points

f (x) = \frac{( 4 x - 12 )}{( x - 2 ) ^{2}}

x = 4

Solution steps

\frac{4 x - 12}{( x - 2 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x - 12}{( x - 2 ) ^{2}} : x < 2 or x > 2

\frac{4 x - 12}{( x - 2 ) ^{2}}

is not defined at

x = 2

, therefore:

x = 4

f (x, y) = (1 - x^{2})^{2} - y^{2}

f (x) = (x^{2})

f (x, y) = x^{2} y - y^{3} - x^{2} - y^{2} + 1

f (x) = \frac{2}{3} x^{\frac{3}{2}} - \frac{2}{5} x^{\frac{5}{2}}

f (x) = 3 x^{\frac{1}{2}} - x^{\frac{3}{2}}

What is the critical f(x)=((4x-12))/((x-2)^2) ?
The critical f(x)=((4x-12))/((x-2)^2) is x=4