What is the inverse of f(x)=((3x-3))/(x+6) ?

The inverse of f(x)=((3x-3))/(x+6) is (-3-6x)/(x-3)

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inverse of f(x)=((3x-3))/(x+6)

inverse

f (x) = \frac{( 3 x - 3 )}{x + 6}

\frac{- 3 - 6 x}{x - 3}

Solution steps

y = \frac{3 x - 3}{x + 6}

Replace

x

with

y

x = \frac{3 y - 3}{y + 6}

Solve for

y, x = \frac{3 y - 3}{y + 6}

\frac{- 3 - 6 x}{x - 3}

- x^{2} + 2 x - 1

(- 1, 1), (- 2, - 1)

6 x - x^{2} - 5

f (x) = e^{- t}

x^{2} - 8 x + 12

What is the inverse of f(x)=((3x-3))/(x+6) ?
The inverse of f(x)=((3x-3))/(x+6) is (-3-6x)/(x-3)