What is the critical f(x)=3x^3-3x^2-3x-1 ?

The critical f(x)=3x^3-3x^2-3x-1 is x=-1/3 ,x=1

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critical f(x)=3x^3-3x^2-3x-1

critical points

f (x) = 3 x^{3} - 3 x^{2} - 3 x - 1

x = - \frac{1}{3}, x = 1

Solution steps

3 x^{3} - 3 x^{2} - 3 x - 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

3 x^{3} - 3 x^{2} - 3 x - 1 : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{3}, x = 1

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 5

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 4

3 x^{4} - 4 x^{3} - 12 x + 1

f (x) = \frac{( 2 x - 1 )}{x ^{2} - 4 x - 5}

F (t) = 2 t \frac{2}{3} + t \frac{5}{3}

What is the critical f(x)=3x^3-3x^2-3x-1 ?
The critical f(x)=3x^3-3x^2-3x-1 is x=-1/3 ,x=1