What is the critical f(x)=(x-4)^{2/3} ?

The critical f(x)=(x-4)^{2/3} is x=4

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critical f(x)=(x-4)^{2/3}

critical points

f (x) = (x - 4)^{\frac{2}{3}}

x = 4

Solution steps

(x - 4)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4

Identify critical points not in

f (x)

domain

Domain of

(x - 4)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = 4

7 x - 8 y + 2 x y - x^{2} + y^{3}

f (x) = 9 x + 6 x^{- 1}

2 x^{3} - 9 x^{2} - 24 x + 1

3 x^{4} + 4 x^{3} - 12 x^{2} + 10

f (x) = x^{2} (x + 4)^{3}