What is the critical f(x)=9x+6x^{-1} ?

The critical f(x)=9x+6x^{-1} is x=-sqrt(2/3),x=sqrt(2/3)

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critical f(x)=9x+6x^{-1}

critical points

f (x) = 9 x + 6 x^{- 1}

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

9 x + 6 x^{- 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

9 x + 6 x^{- 1} : x < 0 or x > 0

9 x + 6 x^{- 1}

is not defined at

x = 0

, therefore:

x = - \frac{2}{3}, x = \frac{2}{3}

2 x^{3} - 9 x^{2} - 24 x + 1

3 x^{4} + 4 x^{3} - 12 x^{2} + 10

f (x) = x^{2} (x + 4)^{3}

f (x) = x^{4} e^{x}

x + \frac{16}{x}

What is the critical f(x)=9x+6x^{-1} ?
The critical f(x)=9x+6x^{-1} is x=-sqrt(2/3),x=sqrt(2/3)