en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical x+(16)/x

Solution

critical points

x + \frac{16}{x}

Solution

x = - 4, x = 4

Solution steps

x + \frac{16}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 4, x = 0

Identify critical points not in

f (x)

domain

Domain of

x + \frac{16}{x} : x < 0 or x > 0

x + \frac{16}{x}

is not defined at

x = 0

, therefore:

x = - 4, x = 4

Popular Examples

critical y=sin(2x)critical points

y = sin (2 x)

critical f(x)=-e^x(x-4)critical points

f (x) = - e^{x} (x - 4)

critical f(x)=e^y(y^2-x^2)critical points

f (x) = e^{y} (y^{2} - x^{2})

critical f(x)=(x^2-1)/(x^3)critical points

f (x) = \frac{x ^{2} - 1}{x ^{3}}

critical f(x)=(x^2-25)^7 critical points

f (x) = (x^{2} - 25)^{7}

Frequently Asked Questions (FAQ)

What is the critical x+(16)/x ?
The critical x+(16)/x is x=-4,x=4