What is the critical y=sin(2x) ?

The critical y=sin(2x) is x= pi/4+pin,x=(3pi)/4+pin

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critical y=sin(2x)

critical points

y = sin (2 x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

sin (2 x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Identify critical points not in

f (x)

domain

Domain of

sin (2 x) : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

f (x) = - e^{x} (x - 4)

f (x) = e^{y} (y^{2} - x^{2})

f (x) = \frac{x ^{2} - 1}{x ^{3}}

f (x) = (x^{2} - 25)^{7}

f (x) = 2 x^{3} - 24 x

What is the critical y=sin(2x) ?
The critical y=sin(2x) is x= pi/4+pin,x=(3pi)/4+pin