What is the critical f(x)=x^6e^{-8x} ?

The critical f(x)=x^6e^{-8x} is x=0,x= 3/4

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critical f(x)=x^6e^{-8x}

critical points

f (x) = x^{6} e^{- 8 x}

x = 0, x = \frac{3}{4}

Solution steps

x^{6} e^{- 8 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{3}{4}

Identify critical points not in

f (x)

domain

Domain of

x^{6} e^{- 8 x} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{3}{4}

f (x) = 8 x^{2} - x^{4}

4 x^{3} - x^{2} - 4 x + 3

f (x) = \frac{1}{2 x - 1}

f (x) = x^{6} e^{- 7 x}

f (x) = 6 x^{2} + 6 x - 36

What is the critical f(x)=x^6e^{-8x} ?
The critical f(x)=x^6e^{-8x} is x=0,x= 3/4