What is the critical f(x)=(2x)/(x^2-1) ?

The critical f(x)=(2x)/(x^2-1) is None

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critical f(x)=(2x)/(x^2-1)

critical points

f (x) = \frac{2 x}{x ^{2} - 1}

None

Solution steps

\frac{2 x}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

\frac{2 x}{x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

None

f (x) = x^{3} - 4 x^{2} + 4 x

\frac{6 x}{( x ^{2} + 3 ) ^{2}}

x^{3} - 12 x^{2} + 36 x

f (x) = \frac{x ^{2} - 1}{x ^{2} + 2 x - 3}

f (x) = \frac{( x ^{2} - 16 )}{( 2 x ^{2} + 7 x - 15 )}