What is the critical g(y)=((y-1))/(y^2-y+1) ?

The critical g(y)=((y-1))/(y^2-y+1) is y=0,y=2

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critical g(y)=((y-1))/(y^2-y+1)

critical points

g (y) = \frac{( y - 1 )}{y ^{2} - y + 1}

y = 0, y = 2

Solution steps

\frac{y - 1}{y ^{2} - y + 1}

Find where

f^{'} (y)

is equal to zero or undefined

y = 0, y = 2

Identify critical points not in

f (y)

domain

Domain of

\frac{y - 1}{y ^{2} - y + 1} : - \infty < y < \infty

All critical points are in domain

y = 0, y = 2

- 3 x^{2} + 6 x

f (x, y) = x^{3} + x^{2} y + x - y

f (x) = ln (x) + 1

y = x^{3} - 3 x^{2} + b

f (x) = (9 x^{2} ln (x))

What is the critical g(y)=((y-1))/(y^2-y+1) ?
The critical g(y)=((y-1))/(y^2-y+1) is y=0,y=2