What is the critical f(x)=x^3+y^3-3xy+1 ?

The critical f(x)=x^3+y^3-3xy+1 is (0,0),(1,1)

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critical f(x)=x^3+y^3-3xy+1

critical points

f (x) = x^{3} + y^{3} - 3 x y + 1

(0, 0), (1, 1)

Solution steps

x^{3} + y^{3} - 3 x y + 1

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (1, 1)

f (x, y) = 2 x + 8 x^{5} + 7 y + 6 y^{3}

f (x) = 3 x^{2} - 4 x^{3}

y^{3} + 3 x^{2} y - 6 x^{2} - 6 y^{2} + 2

f (x) = \frac{- 2 ( x + 1 )}{( x - 2 ) ^{4}}

f (x) = 5 - 2 x^{2} + 3 x^{3} - x^{4}

What is the critical f(x)=x^3+y^3-3xy+1 ?
The critical f(x)=x^3+y^3-3xy+1 is (0,0),(1,1)