What is the critical f(x)=(-2(x+1))/((x-2)^4) ?

The critical f(x)=(-2(x+1))/((x-2)^4) is x=-2

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critical f(x)=(-2(x+1))/((x-2)^4)

critical points

f (x) = \frac{- 2 ( x + 1 )}{( x - 2 ) ^{4}}

x = - 2

Solution steps

\frac{- 2 ( x + 1 )}{( x - 2 ) ^{4}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{- 2 ( x + 1 )}{( x - 2 ) ^{4}} : x < 2 or x > 2

\frac{- 2 ( x + 1 )}{( x - 2 ) ^{4}}

is not defined at

x = 2

, therefore:

x = - 2

f (x) = 5 - 2 x^{2} + 3 x^{3} - x^{4}

f (x) = x^{2} - 8 ln (7 x)

f (x, y) = x^{2} - 2 x + y^{2} + 2 y + 1

f (x) = (\frac{x ^{4}}{4} - x^{3} - 2 x^{2} + 3)

f (x) = 14 10 π x + \frac{160}{x}

What is the critical f(x)=(-2(x+1))/((x-2)^4) ?
The critical f(x)=(-2(x+1))/((x-2)^4) is x=-2