What is the critical f(x,y)=x^4+y^4-4xy+2 ?

The critical f(x,y)=x^4+y^4-4xy+2 is (0,0),(-1,-1),(1,1)

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critical f(x,y)=x^4+y^4-4xy+2

critical points

f (x, y) = x^{4} + y^{4} - 4 x y + 2

(0, 0), (- 1, - 1), (1, 1)

Solution steps

x^{4} + y^{4} - 4 x y + 2

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (- 1, - 1), (1, 1)

y = x^{3} - 6 x^{2} + 9 x - 2

y = 3 x \cdot e^{x}

f (x) = \frac{( x ^{2 - 1} )}{( 2 x + 1 )}

- 0.5 x^{2} + 0.3 x

f (x) = 1 - x^{2}

What is the critical f(x,y)=x^4+y^4-4xy+2 ?
The critical f(x,y)=x^4+y^4-4xy+2 is (0,0),(-1,-1),(1,1)