What is the critical f(x)=((2x-1))/(x+1) ?

The critical f(x)=((2x-1))/(x+1) is None

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critical f(x)=((2x-1))/(x+1)

critical points

f (x) = \frac{( 2 x - 1 )}{x + 1}

None

Solution steps

\frac{2 x - 1}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x - 1}{x + 1} : x < - 1 or x > - 1

\frac{2 x - 1}{x + 1}

is not defined at

x = - 1

, therefore:

None

f (x, y) = \frac{x ^{2}}{2} - x y^{3} + x

- \frac{2 x ( - x ^{2} + 27 )}{( x ^{2} + 9 ) ^{3}}

f (x) = x^{\frac{3}{2}} (3 x + 10)

\frac{2 ( x ^{2} - 9 )}{x ^{2} - 4}

f (x) = \frac{1 - x}{( x + 1 ) ^{3}}

What is the critical f(x)=((2x-1))/(x+1) ?
The critical f(x)=((2x-1))/(x+1) is None