What is the critical f(x)=((x^2)/(sqrt(x+1))) ?

The critical f(x)=((x^2)/(sqrt(x+1))) is x=0

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critical f(x)=((x^2)/(sqrt(x+1)))

critical points

f (x) = (\frac{x ^{2}}{x + 1})

x = 0

Solution steps

\frac{x ^{2}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x + 1} : x > - 1

\frac{x ^{2}}{x + 1}

is not defined at

x = - 1

, therefore:

x = 0

f (x) = x^{2} + y^{2} - 6 = 0

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 8

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 4

f (x) = x^{3} ln (x^{2})

f (x) = \frac{5}{x + 2} - 1

What is the critical f(x)=((x^2)/(sqrt(x+1))) ?
The critical f(x)=((x^2)/(sqrt(x+1))) is x=0