What is the critical f(x)=(x^2+3x-40)/(x+1) ?

The critical f(x)=(x^2+3x-40)/(x+1) is None

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critical f(x)=(x^2+3x-40)/(x+1)

critical points

f (x) = \frac{x ^{2} + 3 x - 40}{x + 1}

None

Solution steps

\frac{x ^{2} + 3 x - 40}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 3 x - 40}{x + 1} : x < - 1 or x > - 1

\frac{x ^{2} + 3 x - 40}{x + 1}

is not defined at

x = - 1

, therefore:

None

f (x) = (x + 8)^{\frac{2}{3}}

f (x) = \frac{( x + 3 )}{x ^{2} - 5 x + 6}

f (x) = x^{4} - \frac{3 x ^{2}}{2} - x + \frac{29}{16}

y = 8 - (x + 3)^{2}

f (x, y) = y^{3} + 3 x^{2} - 6 x y - 9 y - 2

What is the critical f(x)=(x^2+3x-40)/(x+1) ?
The critical f(x)=(x^2+3x-40)/(x+1) is None