What is the critical f(x)=sqrt(|x|)+x/3 ?

The critical f(x)=sqrt(|x|)+x/3 is x=-9/4 ,x=0

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critical f(x)=sqrt(|x|)+x/3

critical points

f (x) = ∣ x ∣ + \frac{x}{3}

x = - \frac{9}{4}, x = 0

Solution steps

∣ x ∣ + \frac{x}{3}

Absolute value functions are piecewise functions

Find the function intervals:

x < 0, x = 0, x > 0

Evaluate the function behavior for each interval

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{9}{4}, x = 0

f (x, y) = x^{2} - 4 x y + 3 y^{2} + 2 x - 4 y

f (x) = \frac{( 3 + x ) ^{2} ( 4 - x )}{x ^{2} + 7}

f (x) = 2 x - x^{2}

f (x) = x^{2} + 8 x + 19

f (x) = x^{3} + 2 x^{2} - 4 x

What is the critical f(x)=sqrt(|x|)+x/3 ?
The critical f(x)=sqrt(|x|)+x/3 is x=-9/4 ,x=0