What is the critical (3x^2-11)/(x^2-4) ?

The critical (3x^2-11)/(x^2-4) is x=0

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critical (3x^2-11)/(x^2-4)

critical points

\frac{3 x ^{2} - 11}{x ^{2} - 4}

x = 0

Solution steps

\frac{3 x ^{2} - 11}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x ^{2} - 11}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{3 x ^{2} - 11}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = 2 x^{3} - 15 x^{2} + 24 x

f (x, y) = x y - \frac{1}{x} - \frac{1}{y}

f (x) = \frac{x ^{2} - 4}{x ^{2} - 2 x}

y = x^{3}

3 x^{2} - 4 x^{3}