What is the critical cos(6x),0<= x<= pi/2 ?

The critical cos(6x),0<= x<= pi/2 is x=0,x= pi/6 ,x= pi/3 ,x= pi/2

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critical cos(6x),0<= x<= pi/2

critical points

cos (6 x), 0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{π}{6}, x = \frac{π}{3}, x = \frac{π}{2}

Solution steps

cos (6 x), 0 \leq x \leq \frac{π}{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{6}, x = \frac{π}{3}

Identify critical points not in

f (x)

domain

Domain of

cos (6 x), 0 \leq x \leq \frac{π}{2} : 0 \leq x \leq \frac{π}{2}

All critical points are in domain

x = \frac{π}{6}, x = \frac{π}{3}

Evaluate interval endpoint

x = 0 :

critical point

Evaluate interval endpoint

x = \frac{π}{2} :

critical point

x = 0, x = \frac{π}{6}, x = \frac{π}{3}, x = \frac{π}{2}

\frac{2 x ^{2} + 5}{x ^{2} - 25}

f (x) = - 12 x - 12

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5}

f (x) = x^{2} + 2 x y + 2 y^{2} - 6 x + 10 y + 4

3 x^{2} + 2 x + 5

What is the critical cos(6x),0<= x<= pi/2 ?
The critical cos(6x),0<= x<= pi/2 is x=0,x= pi/6 ,x= pi/3 ,x= pi/2