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Popular >

distance (4,-5),(0,0)

Solution

distance

(4, - 5), (0, 0)

Solution

41

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, - 5)

and

(0, 0)

is

= (0 - 4)^{2} + (0 - (- 5))^{2}

Simplify

= 41

Popular Examples

domain of-1/9 x^3-3 domain

- \frac{1}{9} x^{3} - 3

range of f(x)=(x-4)^2+1 range

f (x) = (x - 4)^{2} + 1

domain of f(x)=10x-9 domain

f (x) = 10 x - 9

domain of f(x)=(x+2)/(x^2+6x+8)domain

f (x) = \frac{x + 2}{x ^{2} + 6 x + 8}

perpendicular y=-8x+7,(5,-3)perpendicular

y = - 8 x + 7, (5, - 3)

Frequently Asked Questions (FAQ)

What is the distance (4,-5),(0,0) ?
The distance (4,-5),(0,0) is square root of 41