What is the asymptotes of f(x)=(x^2-x)/(sqrt(x^2-1)) ?

The asymptotes of f(x)=(x^2-x)/(sqrt(x^2-1)) is Vertical: x=-1

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asymptotes of f(x)=(x^2-x)/(sqrt(x^2-1))

asymptotes

f (x) = \frac{x ^{2} - x}{x ^{2} - 1}

Vertical : x = - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - x}{x ^{2} - 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - x}{x ^{2} - 1} :

None

Vertical : x = - 1

f (x) = \frac{2 x + 10}{x ^{2} - 16}

f (x) = \frac{2 x + 4}{- x ^{2} + 4}

f (x) = \frac{6}{x ^{2} + 5 x - 6}

f (x) = \frac{3 x + 6}{x ^{2} + 8 x - 9}

f (x) = \frac{3 + x - x ^{2}}{x - 2}

What is the asymptotes of f(x)=(x^2-x)/(sqrt(x^2-1)) ?
The asymptotes of f(x)=(x^2-x)/(sqrt(x^2-1)) is Vertical: x=-1