What is the asymptotes of f(x)=(2x^2-2x)/(5x-5) ?

The asymptotes of f(x)=(2x^2-2x)/(5x-5) is Slant: y= 2/5 x

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asymptotes of f(x)=(2x^2-2x)/(5x-5)

asymptotes

f (x) = \frac{2 x ^{2} - 2 x}{5 x - 5}

Slant : y = \frac{2}{5} x

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 2 x}{5 x - 5} :

None

Horizontal Asymptotes of

\frac{2 x ^{2} - 2 x}{5 x - 5} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 2 x}{5 x - 5} : y = \frac{2}{5} x

Slant : y = \frac{2}{5} x

f (x) = x^{2} ln (x)

f (x) = \frac{x ^{2} - 8}{x - 4}

\frac{2 x - 1}{x e ^{x}}

\frac{1}{2} x - \frac{6}{x}

f (x) = \frac{x - 4}{2 ( x - 1 ) ( x - 4 )}

What is the asymptotes of f(x)=(2x^2-2x)/(5x-5) ?
The asymptotes of f(x)=(2x^2-2x)/(5x-5) is Slant: y= 2/5 x