What is the asymptotes of f(x)=((2-4x^2))/((x^2-1)) ?

The asymptotes of f(x)=((2-4x^2))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=-4

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asymptotes of f(x)=((2-4x^2))/((x^2-1))

asymptotes

f (x) = \frac{( 2 - 4 x ^{2} )}{( x ^{2} - 1 )}

Vertical : x = - 1, x = 1, Horizontal : y = - 4

Solution steps

Vertical asymptotes of

\frac{2 - 4 x ^{2}}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{2 - 4 x ^{2}}{x ^{2} - 1} : y = - 4

Slant Asymptotes of

\frac{2 - 4 x ^{2}}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = - 4

∣ x ∣

f (x) = arctan (e^{x})

f (x) = (2. 5^{x}) - 6

f (x) = \frac{x ^{2} + 3 x + 2}{x - 2}

f (x) = \frac{4}{x ^{2} - 9}

What is the asymptotes of f(x)=((2-4x^2))/((x^2-1)) ?
The asymptotes of f(x)=((2-4x^2))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=-4